-
The heavy quark spin structure [42] can be expressed in terms of the heavy-light basis from the hadron basis. A similar example is given by the
$ Z^{(\prime)}_c $ and$ Z_b^{(\prime)} $ case with two heavy quarks in Refs. [43-48]. Likewise, the S-wave$ \bar{D}^{(*)}K^{(*)} $ system, with only one heavy quark, can be written in terms of the heavy degree of freedom,${1}/{2}$ , and light degree of freedom,$ s_l $ , as follows [49]$ \begin{aligned}[b] |{({\bar c_{{j_1}}}{q_{{j_2}}})_{{j_{12}}}}{(\bar s{q^\prime })_{{j_3}}}{\rangle _J} =& \sum\limits_{{s_l}} {{{\left( { - 1} \right)}^{{j_2} + {j_3} + {j_{12}} + {s_l}}}} \left\{ {\begin{array}{*{20}{c}} {{j_1}}&{{j_2}}&{{j_{12}}}\\ J&{{j_3}}&{{s_l}} \end{array}} \right\}\\&\times\widehat {{j_{12}}}\widehat {{s_l}}|{\bar c_{{j_1}}}{({q_{{j_2}}}{(\bar s{q^\prime })_{{j_3}}})_{{s_l}}}\rangle \end{aligned}$
(1) with
$ \hat{j} = \sqrt{2j+1} $ . Here,$ j_1 = \dfrac{1}{2} $ ,$ j_2 = \dfrac{1}{2} $ , and$ j_{12} = 0,1 $ are spins of anti-charm quark$ \bar{c} $ , light quark q, and their sum in the$ \bar{D}^{(*)} $ meson, respectively;$ j_3 = 0,1 $ and$ J = 0,1,2 $ are the spins of the$ K^{(*)} $ meson and the total spin of the$ \bar{D}^{(*)}K^{(*)} $ system, respectively; and$ s_l $ on the right hand side of Eq. (1) is the light degree of freedom of the system, which is the only relevant quantity for the dynamics in the heavy quark limit. Following Eq. (1), one can obtain the decompositions of the$ \bar{D}^{(*)}K^{(*)} $ system as$ |\bar{D}K\rangle_{0^+} = \Big|\frac{1}{2}\Big\rangle, $
(2) $ |\bar{D}^*K\rangle_{1^+} = \Big|\frac{1}{2}\Big\rangle , $
(3) $ |\bar{D}K^*\rangle_{1^+} = \frac{1}{\sqrt{3}}\Big|\frac{1}{2}\Big\rangle^*+\sqrt{\frac{2}{3}}\Big|\frac{3}{2}\Big\rangle^*, $
(4) $ |\bar{D}^*K^*\rangle_{0^+} = -\Big|\frac{1}{2}\Big\rangle^* , $
(5) $ |\bar{D}^*K^*\rangle_{1^+} = \sqrt{\frac{2}{3}}\Big|\frac{1}{2}\Big\rangle^*-\frac{1}{\sqrt{3}}\Big|\frac{3}{2}\Big\rangle^*, $
(6) $ |\bar{D}^*K^*\rangle_{2^+} = \Big|\frac{3}{2}\Big\rangle^*. $
(7) Here, the heavy degree of freedom is suppressed due to the same value, leaving only the light degrees of freedom,
$ s_l $ , in$ |\dots\rangle $ . Although K and$ K^* $ have the same quark content, the light degrees of freedoms in the first two equations and those in the last four equations can be distinguishable owing to the large scale separation of the K and$ K^* $ masses. Similar to the potentials in Ref. [50], through the contact potential, which is defined as$ C_{2l}^{(*)}\equiv^{(*)}\langle l |\hat{H}_{\rm{HQS}}|l\rangle^{(*)}, $
(8) the potentials of the
$ \bar{D}^{(*)}K $ and$ \bar{D}^{(*)}K^* $ systems are$ V_{0^+} = C_{1} , $
(9) $ V_{1^+} = C_{1} , $
(10) and
$ V^*_{0^+} = C^*_{1} , $
(11) $ V_{{1^ + }}^* = \left( {\begin{array}{*{20}{c}} {\dfrac{1}{3}C_1^* + \dfrac{2}{3}C_3^*}&{\dfrac{{\sqrt 2 }}{3}\left( {C_1^* - C_3^*} \right)}\\ {\dfrac{{\sqrt 2 }}{3}\left( {C_1^* - C_3^*} \right)}&{\dfrac{2}{3}C_1^* + \dfrac{1}{3}C_3^*} \end{array}} \right) , $
(12) $ V^*_{2^+} = C^*_{3}, $
(13) $ V_{J^+} $ and$ V^*_{J^+} $ denote the potentials of the$ \bar{D}^{(*)}K $ and$ \bar{D}^{(*)}K^* $ systems, respectively. The subindex$ J^+ $ presents the total spin and parity of the corresponding system. The transition between$ |l\rangle $ and$ |l\rangle^* $ is the higher order contribution, which is set to zero in this study ①. The above decomposition and the corresponding potentials also work for the$ D^{(*)}K^{(*)} $ systems but with different values of$ C_{2l}^{(*)} $ .With the above potentials, the LSE can be solved:
$ T = V+VGT $
(14) with V denoting the potentials for specific channels of a given quantum number. Here, the two-body non-relativistic propagator is
$ \begin{aligned}[b] G_\Lambda(M,m_1,m_2) =& \int\frac{{\rm{d}}^3q}{(2\pi)^3}\frac{1}{M-m_1-m_2-{{q}}^2/(2\mu)}\\ =& \Lambda+ {\rm i}\frac{m_1 m_2}{2\pi(m_1+m_2)}\sqrt{2\mu (M-m_1-m_2)} \end{aligned}$
with the power divergence subtraction [51] employed to regularize the ultraviolet (UV) divergence. The value of
$ \Lambda $ should be small enough to preserve the heavy quark symmetry, leaving the physics insensitive to the details of short-distance dynamics [50]. Here,$ m_1 $ ,$ m_2 $ , and$ \mu $ are the masses of the two intermediate particles and their reduced mass, respectively, and M is the total energy of the system. The expression of the second Riemann sheet,$ G^{\rm{II}}_\Lambda(M,m_1,m_2) $ , can be obtained by changing the sign of the second term of$ G_\Lambda(M,m_1,m_2) $ . -
Before presenting the numerical results, we estimate the values of the contact potential,
$ C_1 $ . The leading contact terms between heavy-light mesons and Goldstone bosons can be obtained using the following Lagrangian [52-57]:$ {\cal{L}}_{D\phi}^{(1)} = {\cal{D}}_{\mu}D{\cal{D}}^{\mu}D^{\dagger}-M_{0}^{2}DD^{\dagger}, $
(15) where
$ {\cal{D}}_{\mu}H = H\left(\overset\leftarrow{\partial}_{\mu}+\Gamma_{\mu}^{\dagger}\right),\quad{\cal{D}}_{\mu}H^{\dagger} = \left(\partial_{\mu}+\Gamma_{\mu}\right)H^{\dagger}, $
(16) with
$ H\in\left\{ D,D^{*}\right\} ,\quad D^{(*)} = \left(D^{(*)0},D^{(*)+},D_{s}^{(*)+}\right) $
(17) and chiral connection
$ \Gamma_{\mu} = \left(u^{\dagger}\partial_{\mu}u+u\partial_{\mu}u^{\dagger}\right)/2. $
(18) Here, the chiral building blocks are
$ u_{\mu} = {\rm i}\left[u^{\dagger}\partial_{\mu}u-u\partial_{\mu}u^{\dagger}\right],\quad U = u^{2},\quad\chi^{\pm} = u^{\dagger}\chi u^{\dagger}\pm u\chi^{\dagger}u. $
where
$U = \exp\left({\rm i}\sqrt{2}\phi/f_0\right)$ , with$ \phi $ denoting the Goldstone boson octet. To the leading order,$ f_0 $ is the pion decay constant. The isospin singlet$ J^P = 0^+ $ $ DK $ and$ \bar{D}K $ systems are defined as$ D_{s0}^{*+}(2317)\equiv\frac{1}{\sqrt{2}}\left(D^{0}K^{+}-D^{+}K^{0}\right), $
(19) which is associated with the
$ D_{s0}^{*+}(2317) $ and$ X^\prime_{0}\equiv\frac{1}{\sqrt{2}}\left(D^{0}\bar{K}^{0}+D^{+}K^{-}\right). $
(20) The definitions of the isospin singlet
$ J^P = 1^+ $ $ D^*K $ and$ \bar{D}^*K $ systems are similar. From Eq. (15), we obtain$ V_{D_{s0}^{*+}(2317)} = V_{D_{s1}^{+}(2460)}, $
(21) which agrees with those obtained from the heavy-light decomposition, i.e., Eqs. (9), (10), and
$ V_{D_{s0}^{*+}(2317)} = 2V_{X_0}. $
(22) As a result, the value of
$ C_1 $ for the$ \bar{D}^{(*)}K $ system is half of that for the$ D^{(*)}K $ system. Note that any parameter set, i.e.,$ (\Lambda, C_1) $ , for the existence of the$ D_{s0}^*(2317) $ and$ D_{s1}(2460) $ as$ DK $ and$ D^*K $ molecular states (both bound and virtual states) does not indicate the existence of the analogous$ \bar{D}K $ and$ \bar{D}^*K $ molecules. From this point on, we focus on the discussion of the formation of the$ \bar{D}^{(*)}K^{(*)} $ molecule instead of their isospin breaking effect. The isospin average masses, expressed as$ m_D = 1.867\; {\rm{GeV}},\quad m_{D^*} = 2.009\; {\rm{GeV}} $
(23) $ m_K = 0.496\; {\rm{GeV}},\quad m_{K^*} = 0.892\; {\rm{GeV}} $
(24) are considered in this letter.
Concerning the
$ \bar{D}^{(*)}K^* $ interaction, the$ X_0(2900) $ recently observed by the LHCb collaboration is assumed to be a$ I(J^P) = 0(0^+) $ $ \bar{D}^*K^* $ molecular state [58]. We consider two cases for the$ X_0(2900) $ ● a bound state, with the
$ X_0(2900) $ mass$ m_{X_0(2900)} $ satisfying$ 1-C_1^* G_\Lambda(m_{X_0(2900)},m_{\bar{D}^*},m_{K^*}) = 0 . $
(25) ● a virtual state, with the
$ X_0(2900) $ mass$ m_{X_0(2900)} $ satisfying$ 1-C_1^* G^{\rm{II}}_\Lambda(m_{X_0(2900)},m_{\bar{D}^*},m_{K^*}) = 0. $
(26) We consider
$ \Lambda = 0.05\; {\rm{GeV}} $ and$ \Lambda = 0.03\; {\rm{GeV}} $ to illustrate the mass positions of its heavy quark spin partners and the corresponding properties.For the bound state solution of the
$ X_0(2900) $ ,$ C_1^* = 33.56\; {\rm{GeV}}^{-2} $ and$ C_1^* = 102.09\; {\rm{GeV}}^{-2} $ correspond to$ \Lambda = 0.05\; {\rm{GeV}} $ and$ \Lambda = 0.03\; {\rm{GeV}} $ , respectively. Fig. 1 shows how the poles move with the variation of the two parameter sets. The blue triangle and green square curves show the pole trajectory of the bound state and resonance in the$ 1^+ $ channel, respectively. Note that, with$ C^*_3 $ varying between$ 40\; {\rm{GeV}}^{-2} $ and$ 170\; {\rm{GeV}}^{-2} $ , one bound state and one resonance emerge with tens of MeV below the$ \bar{D}K^* $ and$ \bar{D}^*K^* $ thresholds, respectively. The bound state in the$ 2^+ $ channel is more sensitive to parameter$ C_3^* $ . Assuming that light quark spin symmetry also works here in similar terms to that for the two$ Z_b $ states [59], i.e.,$ C^*_3 = C^*_1 $ , the pole position of the above three states areFigure 1. (color online)
$ X_0(2900) $ is assumed to be a$ I(J^P) = 0(0^+) $ $ \bar{D}^*K^* $ bound state. The values of$ C_1^* = 33.56\; {\rm{GeV}}^{-2} $ and$ C_1^* = 102.09\; {\rm{GeV}}^{-2} $ are obtained for$ \Lambda = 0.05\; {\rm{GeV}} $ and$ \Lambda = 0.03\; {\rm{GeV}} $ , respectively. The$ 2^+ $ (red circles) and the lower$ 1^+ $ (blue triangles) behave as bound states. The higher$ 1^+ $ (green squares) is a resonance between the$ \bar{D}K^* $ and$ \bar{D}^*K^* $ thresholds. The pole trajectories of these three states with the increasing$ C_3^* $ are shown in the figures. The black arrows indicate the direction of the increasing$ C_3^* $ . The black stars are the mass positions in the light quark spin symmetry.$ m_{2^+} = 2.866\; {\rm{GeV}}, $
(27) $ m_{1^+} = 2.722\; {\rm{GeV}},\quad m_{1^+} = 2.866\; {\rm{GeV}} . $
(28) The vanishing imaginary part of the higher
$ 1^+ $ state is because of the degenerance of the two$ 1^+ $ states.For the virtual state solution of the
$ X_0(2900) $ ,$ C_1^* = 14.24\; {\rm{GeV}}^{-2} $ and$ C_1^* = 19.92\; {\rm{GeV}}^{-2} $ correspond to$ \Lambda = 0.05\; {\rm{GeV}} $ and$ \Lambda = 0.03\; {\rm{GeV}} $ , respectively. Fig. 2 shows how the poles move with$ C^*_3 $ variation between$ 22\; {\rm{GeV}}^{-2} $ and$ 36\; {\rm{GeV}}^{-2} $ for the two$ \Lambda $ values. For the former case, the blue triangles and red circles show the pole trajectories of the bound states for the$ 1^+ $ and$ 2^+ $ channels, respectively. For the latter case, both of them become virtual states. Consequently, whether the higher$ 1^+ $ $ \bar{D}^*K^* $ molecule exists or not depends on the nature of the$ X_0(2900) $ , i.e., either a bound state or a virtual state, which can be studied through further detailed scanning of its line shape. Thus, searching for these heavy quark spin partners would help to reveal the nature of the$ X_0(2900) $ .Figure 2. (color online)
$ X_0(2900) $ is assumed to be a$ I(J^P) = 0(0^+) $ $ \bar{D}^*K^* $ virtual state. The values of$ C_1^* = 14.24\; {\rm{GeV}}^{-2} $ and$ C_1^* = 19.92\; {\rm{GeV}}^{-2} $ are obtained for$ \Lambda = 0.05\; {\rm{GeV}} $ and$ \Lambda = 0.03\; {\rm{GeV}} $ , respectively. The$ 2^+ $ (red circles) and the lower$ 1^+ $ (blue triangles) behave as bound states for the former case. They behave as virtual states for the latter case. The higher$ 1^+ $ (green squares) is far away from the physical sheet and has marginal physical impact for both cases. The pole trajectories of the two states with increasing$ C_3^* $ are shown in the figures. The black arrows indicate the direction of the increasing$ C_3^* $ .
X0(2900) and its heavy quark spin partners in molecular picture
- Received Date: 2020-10-12
- Available Online: 2021-02-15
Abstract: The