-
First, in terms of the relativistic Schr
${\rm \ddot{o}} $ dinger equation, let us calculate the mass spectra of$ f_0 $ by assuming them to be made of a light quark and an anti-quark. Using the so-called relativistic Schrödinger equation is only an improvement to the regular one. In the Hamiltonian, only the concerned kinetic part of the light quark (anti-quark) adopts the relativistic form and the other part is unchanged. Because the light quarks are not as heavy as c or b quarks, one can believe that the modification may provide a physical picture which is closer to the physical reality. But, of course, it is not like the Dirac equation; it is only an improvement of the non-relativistic Schrödinger equation.In Ref. [23] the authors study the
$ B_c $ meson, which contains two heavy quarks (anti-quarks) through the relativistic Schrödinger equation, while in Refs. [22, 24-25] mesons which contain a heavy quark (anti-quark) and a light quark (anti-quark) were investigated in the same scenario. In Ref. [26] the authors studied$ \phi $ in terms of the relativistic Schrödinger equation and in Ref. [27] the authors studied$ \rho $ and$ \phi $ via the relativistic Schrödinger equation. In Ref. [28] many light mesons with different quantum numbers have been studied in terms of the relativistic Schrödinger equation. In all these studies, obvious improvements were reported, namely the resulting solutions are closer to the data. Since$ f_0 $ mesons are$ 0^{++} $ states, the relative orbital angular momentum$ l = 1 $ . Following Ref. [22], the effective Hamiltonian is$ H = \sqrt{-\nabla^2_1+m_1^2}+\sqrt{-\nabla^2_2+m_2^2}+V_0(r)+H', $
(1) where
$ m_1 $ and$ m_2 $ are the masses of the light quark and anti-quark respectively. In our numerical computations we set$ m_1 = m_2 = 0.3 $ GeV for the u and d quark, and$ m_1 = m_2 = 0.5 $ GeV for the s quark.$ \nabla^2_1 $ and$ \nabla^2_2 $ act on the fields of$ q_1 $ and$ \bar q_2 $ ,$ V_0(r) $ is a combination of the QCD-Coulomb term and a linear confining term [28-30]$ V_0(r) = \dfrac{-4}{3}\frac{\alpha_s(r)}{r}+\kappa r+c. $
(2) Here
$ \alpha_s(r) $ is the coupling constant. For the concerned energy scale of$\Lambda_{\rm QCD}\sim 300$ MeV the non-perturbative QCD effect dominates and so far$ \alpha_s(r) $ cannot be determined by a general principle. Thus, one generally needs to invoke concrete models where the model-dependent parameters are adopted by fitting data. Indeed, theoretical uncertainties are unavoidable. In this work, the running coupling constant$ \alpha_s(r) $ , expressed in terms of a function of coordinates, can be obtained through the Fourier transformation of$ \alpha_s(Q^2) $ . Following Refs. [22, 28], we have$ \alpha_s(r) = \Sigma_i \alpha_i \frac{2}{\sqrt \pi}\int^{\gamma_i r}_0 {\rm e}^{-x^2} {\rm d}x , $
(3) where
$ \alpha_i $ and$ \gamma_i $ are free constants, which were fitted [22, 28] by making the behavior of the running coupling constant$ \alpha_s(r) $ at short distances coincide numerically with$ \alpha_s(Q^2) $ predicted by QCD. In our calculation we follow their work and take$ \alpha_1 = 0.15,\; \alpha_2 = 0.15,\; \alpha_3 = 0.20 $ and$ \gamma_1 = 1/2,\; \gamma_2 = \sqrt {10}/2,\; \gamma_3 = \sqrt {1000}/2 $ .Since we are dealing with the P-wave structure of
$ q\bar q $ , the spin-spin hyperfine interaction and spin-orbit interaction are concerned and an extra Hamiltonian$ H' $ can be written as$ H' = V_{\rm hyp}(r)+V_{\rm so}(r). $
(4) The spin-spin hyperfine interaction is
$ \begin{aligned}[b] V_{\rm hyp}(r) =& \frac{32\pi}{9 m_1 m_2}\alpha_s\delta_\sigma(r){{s}}_1\cdot {{s}}_2 \\ &-\frac{4}{3}\frac{\alpha_s}{m_1 m_2} \frac{1}{ r^3}\left(\frac{3\; {{s}}_1\cdot{{r}}\; {{s}}_2\cdot{{r}} }{r^2}-{{s}}_1\cdot {{s}}_2\right),\end{aligned}$
(5) with [22]
$ \delta_\sigma(r) = \left(\frac{\sigma}{\sqrt \pi}\right)^3 {\rm e}^{-\sigma^2 r^2}, $
(6) where
$ \sigma $ is a phenomenological parameter and$\langle{{s}}_1\cdot{{s}}_2\rangle = 1/4$ .The spin-orbit interaction is
$\begin{aligned}[b] V_{\rm so}(r) = &\frac{4}{3}\frac{\alpha_s}{ r^3}\left(\frac{1}{m_1}+\frac{1}{m_2}\right)\left(\frac{{{s}}_1\cdot{{L}}}{m_1}+ \frac{{{s}}_2\cdot{{L}} }{m_2}\right) \\ &-\frac{1}{2r}\frac{\partial V_0(r)}{\partial r}\left(\frac{{{s}}_1\cdot{{L}}}{m_1^2}+\frac{{{s}}_2\cdot{{L}}}{m_2^2}\right), \end{aligned}$
(7) where
${{L}}$ is the orbital angular momentum between the quark and anti-quark. For the$ 0^{++} $ state, we have$\langle{{s}}_1\cdot{{L}}\rangle = \langle{{s}}_2\cdot{{L}}\rangle = -1$ .Determining the five parameters is a bit tricky. We are dealing with
$ f_0 $ mesons whose contents do not include heavy quarks, so when using the potential model to calculate their mass spectra we need to adopt different schemes from that for heavy quarkonia, to determine the relevant parameters. Our strategy is as follows. We suppose$ f_0(500) $ and$ f_0(980) $ are pure quark states, i.e. mixtures of$ \dfrac{u\bar u + d\bar d}{\sqrt 2} $ (which we abbreviate as$ n\bar n $ ) and$ s\bar s $ , and try to evaluate the mass eigenvalues of$ n\bar n $ and$ s\bar s $ (which are not physical states).We then try to fix the other two parameters
$ \kappa $ and c. We define$ m_{0n\bar n} $ ,$ m_{1n\bar n} $ and$ m_{2n\bar n} $ as the masses of the ground state, first excited state and the second excited state of$ n\bar n $ . Similarly, for$ s\bar s $ we have$ m_{0s\bar s}, m_{1s\bar s},m_{2s\bar s} $ . Since there are no precise data available, according to the analyses made by previous authors we can set several inequalities as:$ m_{f0(500)}\leqslant m_{0n\bar n} < m_{0s\bar s}\leqslant m_{f_0(980)}, $
$ m_{f_0(1370)}\leqslant m_{1n\bar n} < m_{1s\bar s}\leqslant m_{f_0(1710)}, $
$ m_{f_0(2020)} \leqslant m_{2n\bar n} < m_{2s\bar s}\leqslant m_{f_0(2100)}. $
By these criteria, we cannot obtain exact numbers for b and c, but can set ranges for them. Fortunately the ranges are not too wide for further phenomenological applications. To satisfy the above constraints, we obtain
$ \kappa = 0.29 \sim 0.33 $ GeV$ ^2 $ and$ c = -1.72 \sim -1.58 $ GeV. The masses of the ground, first excited and second excited states of$ n\bar n $ and$ s\bar s $ as are obtained as listed in Table 1. From the table, we note that the masses of the ground states of$ n\bar n $ and$ s\bar s $ are respectively$ 626\sim 636 $ MeV and$ 830 \sim 848 $ MeV. We notice that all the achieved values are within certain ranges, but are not fixed numbers, as discussed above.As is supposed,
$ f_0(500) $ and$ f_0(980) $ are mixtures of ground states of$ n\bar n $ and$ s\bar s $ , thus we step forward to deal with the mixing of$ n\bar n $ and$ s\bar s $ to result in the physical eigenstates of$ f_0(500) $ and$ f_0(980) $ . The mixing matrix is written as$ \begin{aligned}[b] \left( \begin{array}{ccc} m_{f_0(500)} & 0 \\ 0 & m_{f_0(980)}\\ \end{array} \right) & = \left( \begin{array}{ccc} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta\\ \end{array} \right) \left( \begin{array}{ccc} m_{\frac{u\bar u + d\bar d}{\sqrt 2}} & \lambda \\ \lambda & m_{s\bar s} \\ \end{array} \right) \left( \begin{array}{ccc} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta\\ \end{array} \right)^{\dagger}\\ & = \left( \begin{array}{ccc} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta\\ \end{array} \right) \left( \begin{array}{ccc} 626\sim636 {\rm MeV} & \lambda \\ \lambda & 830\sim84 {\rm MeV}\\ \end{array} \right) \left( \begin{array}{ccc} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta\\ \end{array} \right)^{\dagger}. \end{aligned} $
(8) (a) principal quantum number n=1 n=2 n=3 eigenvalue of $n\bar n$ $626\sim636$ MeV$1317\sim1353$ MeV$1872\sim1949$ MeVeigenvalue of $s\bar s$ $830\sim848$ MeV$1515\sim1544$ MeV$2060\sim2130$ MeV${\rm (b)}$ $f_0(500)$ $f_0(980)$ $f_0(1370)$ $f_0(1500)$ mass $400\sim550$ MeV$990\pm20$ MeV$1200\sim1500$ MeV$1506\pm6$ MeVdecay width $400\sim700$ MeV$10\sim100$ MeV$200\sim500$ MeV$112\pm9$ MeV$f_0(1710)$ $f_0(2020)$ $f_0(2100)$ mass $1704\pm12$ MeV$1992\pm16$ MeV$2101\pm7$ MeVdecay width $123\pm18$ MeV$442\pm60$ MeV$224^{+23}_{-21}$ MeVTable 1. (a) Theoretically predicted mass spectra of
$ n\bar n $ and$ s\bar s $ with the principal quantum numbers being n = 1, 2 and 3, and (b) masses of the$ f_0 $ family which have been experimentally measured [31].Requiring
$ m_{f_0(500)} = 400\sim550 $ MeV and$m_{f_0(980)} = 990\pm20$ MeV, we find that when$ \lambda = 201\sim263 $ MeV and$ \theta = 30.7^{\circ}\sim33.9^{\circ} $ , our results coincide well with the conclusion of Refs. [32-34].With our strategy, the five parameters of
$ \alpha_s(r) $ , which is running with respect to r,$ \kappa $ , c and$ \lambda $ ,$ \theta $ are determined, even though only certain ranges instead of exact numbers are provided. It is believed that the results are in accordance with the experimental tolerance.It is noted that if one only considers the
$ q\bar q $ structure, the range from a few hundreds of MeV to 2 GeV can only accommodate six P-wave$ 0^{++} $ eigenstates, so the masses of those excited eigenstates of$n\geqslant 3$ or$l\geqslant 3$ would be beyond this range. There indeed exist seven$ 0^{++} $ physical mesons which are experimentally observed within the aforementioned range. This fact signifies that there should exist something else beside the pure$ q\bar q $ structures, and the most favorable candidate is mixtures of glueballs and$ q\bar q $ . This observation inspires all researchers to explore the possible fractions of glueball components in the observed meson states. -
Our work is a phenomenological study and fully based on the available data. As discussed in previous sections, we find that the energy region of
$ 1\sim 2 $ GeV cannot accommodate seven pure$ 0^{++} $ $ q\bar q $ states, so the picture of pure$ q\bar q $ structures is contrary to experimental observations. Thus a scenario with a mixture of glueballs and$ q\bar q $ within this energy region is favored. The decay rates of$ J/\psi\to \gamma+ f_0 $ imply that$ f_0(1370) $ and$ f_0(1500) $ possess larger$ q\bar q $ components, whereas$ f_0(1710) $ has a large fraction of glueball component (see next section for detailed discussion).The lattice estimate suggests that the mass of the
$ 0^{++} $ pure glueball is about 1.5 GeV, so one can naturally conjecture that$ f_0(1370) $ ,$ f_0(1500) $ and$ f(1710) $ are mixtures of$ q\bar q $ and glueballs with certain fractions. The rest of the$ 0^{++} $ $ q\bar q $ states would have negligible probability to mix with glueballs because their masses are relatively far from that of the pure glueball.As an ansatz, we propose that the physical states
$ f_0(1370) $ ,$ f_0(1500) $ and$ f(1710) $ are mixtures of the second excited states of$ |N\rangle = n\bar n $ and$ |S\rangle = |s\bar s\rangle $ with glueball state$ |G\rangle $ . A unitary matrix U transforms them into the physical states as$ \begin{array}{rl} \left( \begin{array}{ccc} |f_0(1370)\rangle \\ |f_0(1500)\rangle \\ |f_0(1710)\rangle \\ \end{array} \right) = U \left( \begin{array}{ccc} |N\rangle \\ |S\rangle \\ |G\rangle \\ \end{array} \right) \end{array} $
(9) and U is a unitary matrix with the compact form
$ U = \left( \begin{array}{ccc} c_{11} & c_{12} & c_{13} \\ c_{21} & c_{22} & c_{23} \\ c_{31} & c_{32} & c_{33}\\ \end{array} \right). $
(10) By imposing the unitary condition on U, we should determine all the elements of U up to an arbitrary phase. Furthermore we will enforce a few additional conditions on the shape of the matrix: (1) the determinant of the matrix must be unity, and (2) the matrix elements must be real. Those requirements serve as a convention for fixing the unitary matrix. The unitary matrix U transforms the unphysical states
$ |N\rangle, |S\rangle $ and$ |G\rangle $ into the physical eigenstates$ |f_0(1370)\rangle, |f_0(1500)\rangle $ and$ |f_0(1710)\rangle $ , and at the same time diagonalizes the mass matrix$ \tilde M $ as$ \begin{array}{rl} M_{f_0} = U \tilde MU^\dagger \end{array} $
(11) with
$ \begin{array}{rl} M_{f_0} = \left( \begin{array}{ccc} m_{f_0(1370)} & 0 & 0 \\ 0 & m_{f_0(1500)} & 0 \\ 0 & 0 & m_{f_0(1710)} \\ \end{array} \right) \end{array} $
(12) and
$ \begin{array}{rl} \tilde M = \left( \begin{array}{ccc} m_N & \lambda_{N-S} & \lambda_{N-G} \\ \lambda_{N-S} & m_S & \lambda_{S-G} \\ \lambda_{N-G} & \lambda_{S-G} & m_G \\ \end{array} \right) \end{array}。 $
(13) Namely,
$ m_{f_0(1370)},\: m_{f_0(1370)} $ , and$ m_{f_0(1710)} $ are the three roots of the equation$ \begin{aligned}[b] m_{f_0}^3 &- m_{f_0}^2(m_G+m_S+m_N)+ m_{f_0}(m_G m_N \\ &+ m_G m_S + m_N m_S - \lambda_{N-G}^2 - \lambda_{S-G}^2 - \lambda_{N-S}^2)\\ & - (\lambda_{N-G}^2 m_S + \lambda_{S-G}^2 m_N + \lambda_{N-S}^2 m_G \\ &- 2\lambda_{N-G}\lambda_{S-G}\lambda_{N-S} - m_N m_S m_G) = 0. \end{aligned} $
(14) Since we know that QCD is flavor blinded, following Ref. [35], the relation
$ \langle u\bar u/d\bar d|H|G\rangle = \langle s\bar s|H|G\rangle $ should be satisfied. Thus we have$ \dfrac{\langle N|H|G\rangle}{\langle S|H|G\rangle} = \dfrac{\langle \dfrac{u\bar u + d\bar d}{\sqrt 2}|H|G\rangle}{\langle s\bar s|H|G\rangle} = \dfrac{\dfrac{1}{\sqrt 2}+ \dfrac{1}{\sqrt 2} }{1} = \sqrt 2 , $
(15) namely
$ \lambda_{N-G} = \sqrt 2 \lambda_{S-G} $ . Furthermore, the phase spaces and off-mass-shell quark effect may also affect the relation between$ \lambda_{N-G} $ and$ \lambda_{S-G} $ , thus in our calculation we set the relation$\dfrac {\lambda_{N-G} }{ \lambda_{S-G}} = 1.3\sim 1.5 $ . Generally, we have three unknowns in the Hermitian matrix$ \tilde M $ :$ \lambda_{N-S},\; \lambda_{S-G} $ and$ m_G $ . There are three independent equations, so we can fix all of the three unknowns. Moreover, the work of Close, Farrar and Li offers an opportunity to determine the relation between$ c_{33} $ and$ b_{1710} $ since we find that in$ f_0(1710) $ the glueball component is dominant (see next section), namely we have the relation$ b_{1710}\sim c_{33}^2 b(R[G]\to gg)\sim c_{33}^2\times 1. $
(16) Carrying out the numerical computations, we obtain the transformation matrix which satisfies all the aforementioned requirements:
$ \begin{array}{rl} U = \left( \begin{array}{ccc} -0.96\sim-0.87 & -0.21\sim-0.07 & -0.45\sim-0.25 \\ 0.14\sim0.41 & -0.94\sim-0.82 & -0.40\sim-0.30 \\ -0.36\sim-0.17 & -0.53\sim-0.32 & 0.80\sim0.92 \\ \end{array} \right) . \end{array} $
(17) With this transformation matrix, by solving the three mass equations, we obtain
$ \begin{array}{rl} \tilde M = \left( \begin{array}{ccc} 1276\sim1398.6{\rm MeV} & -27\sim1 {\rm MeV} & -164\sim-89 {\rm MeV} \\ -27\sim1 {\rm MeV} & 1526\sim1550 {\rm MeV} & -114\sim-63 {\rm MeV} \\ -164\sim-89 {\rm MeV} & -114\sim-63 {\rm MeV} & 1570\sim1661 {\rm MeV} \\ \end{array} \right) , \end{array} $
(18) The masses
$ m_{n\bar n} = 1317\sim 1353 $ MeV and$m_{s\bar s} = 1515\sim 1544$ MeV in Table 1(a) are directly obtained by solving the relativistic Schrödinger equation in the section above. However, for light quarkonia, the parameters$ \alpha_s $ and$ \kappa $ for the linear potential cannot be well determined, so we set a criterion which involves a few physical inequalities to gain$ m_{n\bar n} $ and$ m_{s\bar s} $ within reasonable ranges.Then we input the two values of
$ m_{n\bar n} $ and$ m_{s\bar s} $ into the non-diagonal mass matrix and by solving the secular equation we determine the masses of the physical$ f_0 $ states. In principle we would simultaneously achieve the expected values of the non-diagonal matrix elements along with the physical masses of$ f_0 $ . However, we notice that the secular equation cannot be solved in the usual way, so we adopt an alternative method to simplify the problem. We pre-determine the ranges of the elements of the unitary matrix which diagonalizes the mass matrix and then substitute them into the secular equation to check if the equation can be satisfied, i.e. if all the requirements (unitarity, etc.) are fulfilled. Repeating the process many times, we find that the pre-determined ranges for the masses$ m_{n\bar n} $ and$ m_{s\bar s} $ of the first excited states of$ n\bar n $ and$ s\bar s $ should be shifted slightly, to$ m_{n\bar n} = 1276\sim 1398 $ MeV and$m_{s\bar s} = 1526\sim 1550$ MeV. Obviously, the small shifts do not correspond to any quantitative changes, but indeed are identical, even though the superficial values look a bit different. We can see that the newly obtained ranges roughly overlap with the previous ones.The solutions show that for
$ f_0(1370) $ and$ f_0(1500) $ , the main components are$ q\bar q $ bound states, whereas the glueball component in$ f_0(1710) $ is overwhelmingly dominant. It also suggests the mass of a pure glueball of$ 0^{++} $ to be$ 1570\sim1661 $ MeV. This value is consistent with the results calculated in quenched lattice QCD:$ 1710\pm50\pm80 $ MeV [2],$ 1648\pm58 $ MeV [36],$ 1654\pm83 $ MeV [37] and$ 1622\pm29 $ MeV [38]. -
In this section we calculate the rates of radiative decays
$ J/\psi\to \gamma+ f_0 $ which may expose the structures of various$ f_0 $ states. -
In this section let us briefly introduce the results of Close, Farrar and Li, without going into the details of the derivations. In their pioneering work, it was proposed to determine the fraction of glueball components in a meson via
$ J/\psi\to \gamma+ f_0 $ decay. We especially focus on mixtures of$ f_0(1370) $ ,$ f_0(1500) $ and$ f_0(1710) $ states with glueballs because if they are pure quark-antiquark states, the theoretically estimated values of their mass spectra obviously deviate from the data (see above section). In Refs. [7, 39], for searching glueball fraction, an ideal reaction is the radiative decays of$ J/\psi $ . Close, Farrar and Li formulated the decay branching ratios as$\begin{aligned}[b] &R(J/\psi\to \gamma +f_0) \\ &\quad= R(J/\psi\to \gamma +g g)\frac{c_R x| H_{0^{++}}(x)|^2}{8\pi(\pi^2-9)}\frac{m_{f_0}}{m_\Psi^2}\Gamma(f_0\to g g), \end{aligned}$
(19) where
$x = 1-\dfrac{m_{f_0}^2}{m_\psi^2}$ and$ c_R = 2/3 $ for the$ 0^{++} $ state,$ H_{0^{++}}(x) $ is a loop integral and its numerical result is given in Ref. [7]. The branching ratio b is defined as$ b(f_0\to g g) = \frac{\Gamma(f_0\to g g)}{\Gamma(f_0\to all)}. $
(20) Taking experimental data [31],
${\rm BR}(J/\psi \to \gamma gg) = (8.8\pm1.1)\%$ ,${\rm BR}(J/\psi \to \gamma f_0(1370) \to \gamma K\bar K) = (4.2\pm1.5) \times 10^{-4}$ and${\rm BR}(f_0(1370) \to K\bar K) = (35\pm13)\%$ [40], and we can obtain the branching ratios of$ J/\psi \to \gamma f_0(1370) $ which are listed in Table 2.Table 2.
$ b(f_0\to g g) $ for$ f_0(1370) $ ,$ f_0(1500) $ and$ f_0(1710) $ from experimental data.For
$ f_0(1500) $ , combining${\rm BR}(f_0(1500)\to \pi\pi) = (34.5\pm 2.2){\text{%}}$ and${\rm BR}(f_0(1500)\to \eta\eta) = (6.0\pm0.9){\text{%}}$ with${\rm BR}(J/\psi \to f_0(1500)\gamma \to \pi \pi \gamma) = (1.09\pm 0.24) \times 10^{-4}$ and${\rm BR}(J/\psi \to f_0(1500)\gamma \to \eta \eta \gamma) = (0.17\pm 0.14) \times 10^{-4}$ [31], we have$\begin{aligned}[b] {\rm BR}(J/\psi \to \gamma f_0(1500))(\pi\pi) &= 3.16\times10^{-4}(1\pm22.9{\text{%}}) , \\ &=(3.16\pm0.72)\times10^{-4}\\ {\rm BR}(J/\psi \to \gamma f_0(1500))(\eta\eta) &= 2.83\times10^{-4}(1\pm83.7{\text{%}}) \\ &= (2.83\pm2.37)\times10^{-4}, \end{aligned}$
(21) namely
$ \begin{aligned}[b] &b_{1500}(\pi\pi) = 19.1{\text{%}}(1\pm27.3{\text{%}}) = (19.1\pm5.2){\text{%}} ,\\ &b_{1500}(\eta\eta) = 17.1{\text{%}}(1\pm85.0{\text{%}}) = (17.1\pm14.5){\text{%}} . \end{aligned}$
(22) To consider possible experimental errors, in our later calculations, we use
$ b_{1500} = 0.171\pm0.145(\eta\eta) $ as the input.For
$ f_0(1710) $ , there are two possible ways to get the branching ratio of$ J/\psi\to f_0(1710)+\gamma $ , and we adopt one of them, for which the experimentalists provide the following information on the four sequential channels [31]$ \begin{aligned}[b] &{\rm BR}(J/\psi \to f_0(1710)\gamma \to K\bar K \gamma) = (9.5^{+1.0}_{-0.5})\times 10^{-4} \\ &\qquad\approx (9.5\pm 1.0) \times 10^{-4} , \\ &{\rm BR}(J/\psi \to f_0(1710)\gamma \to \eta \eta \gamma)= (2.4^{+1.2}_{-0.7})\times 10^{-4}, \\ &\qquad\approx (2.4\pm 1.2) \times 10^{-4}\\ &{\rm BR}(J/\psi \to f_0(1710)\gamma \to \pi \pi \gamma) = (3.8\pm 0.5) \times 10^{-4} ,\\ &{\rm BR}(J/\psi \to f_0(1710)\gamma \to \omega \omega \gamma) = (3.1\pm 1.0) \times 10^{-4} ,\\ \end{aligned} $
(23) as well the data on the decay modes of
$ f_0(1710) $ [41, 42]:$ \begin{aligned}[b] &{\rm BR}(f_0(1710)\to K\bar K) = 0.38^{+0.09}_{-0.19}\approx 0.38\pm 0.19;\\ &{\rm BR}(f_0(1710)\to \pi \pi) = 0.039^{+0.002}_{-0.024}\approx 0.039\pm 0.024;\\ &{\rm BR}(f_0(1710)\to \eta \eta) = 0.22\pm 0.12.\\ \end{aligned} $
(24) Because these four channels probably dominate the radiative decay of
$ J/\psi\to f_0(1710)+\gamma $ , as we summarize the four branching ratios, the resultant value should generally be close to unity. A straightforward calculation determines${\rm BR}(J/\psi \to f_0(1710)\gamma) = (18.8\pm 1.9) \times 10^{-4}$ which corresponds to$b_{1710} = 85.5{\text{%}}(1\pm 21.8{\text{%}}) = (85.5\pm 18.6){\text{%}}$ .An alternative approach is that we can directly use the available branching ratios of radiative decays of
$ J/\psi $ to do the same job.$ \begin{aligned}[b] {\rm BR}(J/\Psi\to \gamma +f_0(1710))(K\bar K) &= 25.0\times 10^{-4}(1\pm 52.1{\text{%}}) \\ &= (25.0\pm 13.0) \times 10^{-4}, \\ {\rm BR}(J/\Psi\to \gamma +f_0(1710))(\pi\pi) &= 97.4\times 10^{-4}(1\pm 62.9{\text{%}}) \\ &= (97.4\pm 61.3) \times 10^{-4}, \\ {\rm BR}(J/\Psi\to \gamma +f_0(1710))(\eta\eta) &= 10.9\times 10^{-4}(1\pm 74.0{\text{%}}) \\ &= (10.9\pm 8.1) \times 10^{-4}. \end{aligned} $
(25) We have tried and noted that among the four channels, the calculated
${\rm BR}(J/\Psi\to \gamma +f_0(1710)) (\eta\eta)$ is too small. The reason might originate from the error in measuring$ \Gamma(f_0(1710)\to\eta\eta) $ , whose value is not as reliable as the databook suggests [43]. Thus we only use the first two results for calculating$ b_{1710} $ . Then we obtain the corresponding$ b_{1710} $ values as$ \begin{aligned}[b] &b_{1710} (K\bar K) = 1.14(1\pm 54.6{\text{%}}) = 1.14\pm 0.62\\ &b_{1710} (\pi\pi) = 4.43(1\pm 65.8{\text{%}}) = 4.43\pm 2.91. \end{aligned} $
(26) For
$ b_{1710} (K\bar K) $ , even though the superficial central value of the b factor is above 1.0, when a large experimental error is taken into account, it is comparable with the value of$ b_{1710} = (85.5\pm18.6){\text{%}} $ . The two values are reasonably consistent with each other and this almost confirms that the aforementioned sequential decay channels dominate the radiative decays of$ J/\psi\to f_0(1710)+\gamma $ . Thus for${\rm BR}(J/\psi \to f_0(1710)\gamma)$ we take its experimental value as$ (18.8\pm 1.9) \times 10^{-4} $ .We then obtain all the results which are listed in Table 2.
As indicated in Ref. [7], the width of
$ f_0 $ is determined by the inclusive processes of$ f_0\to gg $ and$ f_0\to q\bar q $ . It is noted that the contribution of the glueball component to the$ gg $ final state is of order 1, as$ b(R[G]\to gg)\sim 1 $ , whereas$ b(R[q\bar q]\to gg) = {\cal O}(\alpha^2_s)\approx 0.1\sim0.2. $
(27) In Fig. 1 we show that the value of
$ b\,(R[q\bar q]\to gg) $ is different if$ f_0 $ is a glueball or$ q\bar q $ bound state; readers can ignore the irrelevant hadronization processes.Figure 1. (a) Mixing between
$ n\bar n $ and$ s\bar s $ , (b)$ J/\psi\to \gamma+ f_0 $ with$ f_0 $ as a$ q \bar q $ bound state, and (c)$ J/\psi\to \gamma+ f_0 $ with$ f_0 $ as a glueball.Combining with the updated experimental data, one can conclude from the pioneer paper of Close et al. that
$ f_0(1370) $ and$ f_0(1500) $ possess larger$ q\bar q $ components whereas$ f_0(1710) $ has a large fraction of glueball consituent. -
Following Refs. [17, 44], we have
$ \begin{aligned}[b] |{\cal M}(F_i\to K\bar K)|^2 =& 2f_1^2\left(r_a {c_{i1}\over\sqrt 2}+ c_{i2}+ 2g_s^{K\bar K}c_{i3}\right)^2 ,\\ |{\cal M}(F_i\to \pi\pi)|^2 =& 6f_1^2\left({c_{i1}\over\sqrt 2}+ g_s^{\pi\pi}c_{i3}\right)^2 ,\\ |{\cal M}(F_i\to \eta\eta)|^2 =& 2f_1^2\left(a_\eta^2 {c_{i1}\over\sqrt 2}+ r_a b_\eta^2 c_{i2}+ g_s^{\eta\eta} \left(a_\eta^2+ b_\eta^2\right) c_{i3}\right.\\ &\left.+ g_{ss} \left(2a_\eta^2+ b_\eta^2+ {4\over\sqrt2}a_\eta b_\eta\right)c_{i3}\right)^2 , \end{aligned} $
(28) where
$ F_i = (f_0(1370),f_0(1500),f_0(1710)) $ ,$ f_1 $ is the coupling constant of the OZI-allowed Feynman diagrams defined in Ref. [44],$ g_s $ is the ratio of the OZI-suppressed coupling constant to that of the OZI-allowed one,$ g_{ss} $ is the ratio of the doubly OZI-suppressed coupling constant to that of the OZI-allowed one, and$ r_a $ denotes a possible$ SU(3) $ breaking effect in the OZI allowed decays [44]. For$ a_\eta $ and$ b_\eta $ we have the relations$ \begin{aligned}[b] &a_\eta = \dfrac{\cos\theta- \sqrt2\sin\theta}{\sqrt3}\\ &b_\eta = -\dfrac{\sin\theta+ \sqrt2\cos\theta}{\sqrt3} \end{aligned} $
(29) with
$ \theta = -14.4^{\circ} $ [44]. References [45, 46] show the relations$ g_s^{\pi\pi}:g_s^{K\bar K}:g_s^{\eta\eta} = 0.834^{+0.603}_{-0.579}:2.654^{+0.372}_{-0.402}:3.099^{+0.364}_{-0.423} $ through lattice calculation. In Ref. [44] the authors take two schemes with$ g_s^{K\bar K}/g_s^{\pi\pi} = 1.55 $ for scheme I and$ 3.15 $ for scheme II. Then for scheme I they take$g_s^{\pi\pi}:g_s^{K\bar K}:g_s^{\eta\eta} = $ $ 1:1.55:1.59 $ and after fitting data obtain$ g_s^{\pi\pi} = -0.48 $ ,$ g_{ss} = 0 $ and$ r_a = 1.21 $ . For scheme II they took$ g_s^{\pi\pi}:g_s^{K\bar K}:g_s^{\eta\eta} = 1:3.15:4.74 $ and obtained$ g_s^{\pi\pi} = 0.10 $ ,$ g_{ss} = 0.12 $ and$ r_a = 1.22 $ . During their fitting process,$ m_{s\bar s} $ and$ m_G $ as input parameters were set in the same ranges as in our article, but for the value of$ m_{n\bar n} $ they took an input parameter$ 100 $ MeV larger than that in our article. Considering the uncertainty of$ g_s^{\pi\pi}:g_s^{K\bar K}:g_s^{\eta\eta} $ , the two sets of parameters do not have a qualitative difference.$ R^{F_i}_{\pi\pi/K\bar K} = \dfrac{\Gamma(F_i \to \pi\pi)}{\Gamma(F_i \to K\bar K)} = 3\dfrac{\left(\dfrac{c_{i1}}{\sqrt 2}+ g_s^{\pi\pi}c_{i3}\right)^2}{\left(r_a \dfrac{c_{i1}}{\sqrt 2}+ c_{i2}+ 2g_s^{K\bar K}c_{i3}\right)^2}\dfrac{p_\pi}{p_K}. $
(30) Then we list the ratios of
$ F_i\to PP $ for our predictions and experimental data in Table 3.experimental value scheme I scheme II $ R^{f_0(1370)}_{\pi\pi/K\bar K} $ $>1 $ $ 3.98\sim11.68 $ $ 1.22\sim1.88 $ $ R^{f_0(1370)}_{\eta\eta/\pi\pi} $ $ 0.01\sim0.05 $ $ 0.12\sim0.21 $ $ R^{f_0(1370)}_{K\bar K/\eta\eta} $ $ 5.53\sim7.44 $ $ 3.84\sim4.31 $ $ R^{f_0(1500)}_{\pi\pi/K\bar K} $ $ 4.1\pm0.5 $ $ 1.81\sim9520.07 $ $ 0.02\sim0.47 $ $ R^{f_0(1500)}_{\eta\eta/\pi\pi} $ $ 0.173\pm0.024 $ $ 8.65\times10^{-5}\sim0.14 $ $ 0.78\sim17.32 $ $ R^{f_0(1500)}_{K\bar K/\eta\eta} $ $ 1.43\pm0.24 $ $ 0.48\sim10.72 $ $ 2.71\sim3.31 $ $ R^{f_0(1710)}_{\pi\pi/K\bar K} $ $ 0.23\pm0.05 $ $ 0.30\sim0.41 $ $ 0.71\sim112.38 $ $ R^{f_0(1710)}_{\eta\eta/\pi\pi} $ $ 2.09\pm0.80 $ $ 0.59\sim0.82 $ $ 9.69\times10^{-4}\sim4.87 $ $ R^{f_0(1710)}_{\eta\eta/K\bar K} $ $ 0.48\pm0.15 $ $ 0.24\sim0.25 $ $ 6.86\times10^{-4}\sim114.20 $ Table 3. Ratios of
$ F_i\to PP $ for our predictions in scheme I and II, and for experimental data. All the experimental data for$ R^{f_0(1370)}_{\pi\pi/K\bar K} $ are taken from the PDG [31]. In the PDG the range of$ R^{f_0(1370)}_{K\bar K/\pi\pi} $ varies from$ 0.08\pm0.08 $ to$ 0.91\pm0.20 $ , thus we only consider$ R^{f_0(1370)}_{\pi\pi/K\bar K}>1 $ here.From the table above we can see that in scheme I the upper limit of
$ R^{f_0(1500)}_{\pi\pi/K\bar K} $ is$ 9520.07 $ . This is caused by the destructive interference between the contributions of the glueball and quarkonia ingredients to$ f_0(1500)\to K\bar K $ ; the lower bound of$ R^{f_0(1500)}_{\eta\eta/\pi\pi} $ is tiny because of a destructive interference between the glueball and quarkonia contributions to$ f_0(1500)\to \eta\eta $ . For scheme II, the destructive interference between the glueball and quarkonia contributions to$ f_0(1710)\to \eta\eta $ and$ K\bar K $ lead the lower bound of$ R^{f_0(1710)}_{\eta\eta/\pi\pi} $ and$ R^{f_0(1710)}_{\eta\eta/K\bar K} $ to be negligible and the upper limit of$ R^{f_0(1710)}_{\pi\pi/K\bar K} $ and$ R^{f_0(1710)}_{\eta\eta/K\bar K} $ to be as large as$ 10^2 $ . Different from Refs. [17, 44] where the authors preferred scheme II, we find that in our calculation scheme I may fit the experimental data better. With scheme I, our theoretical prediction for the ratios of the decay rates for the three channels of$ f_0(1500) $ ($ R^{f_0(1500)}_{\pi\pi/K\bar K} $ ,$ R^{f_0(1500)}_{\eta\eta/\pi\pi} $ and$ R^{f_0(1500)}_{K\bar K/\eta\eta} $ ) deviate only slightly from experimental data, while for scheme II, the theoretical predictions obviously deviate from experimental data. Cheng et al. considered the two schemes based on the lattice results$ g_s^{\pi\pi}:g_s^{K\bar K}:g_s^{\eta\eta} = 0.834^{+0.603}_{-0.579}: 2.654^{+0.372}_{-0.402}:3.099^{+0.364}_{-0.423} $ . Considering the large uncertainty, we believe our theoretical predictions can fulfill the experimental constraints. -
The
$ f_0(1710)\to \gamma\gamma $ decay would be the most sensitive channel to test the glueball fraction inside the hadron because gluons do not directly couple to photons. In early searches for glueballs, the rate of possible glueball decay into photons was considered to be seriously depressed and the mechanism was described by the word “stickiness,” which was the first criterion to identify a glueball. Thus for$ f_0\to \gamma\gamma $ , the amplitude is$ \begin{aligned}[b] M(f_0\to\gamma\gamma) = &c_n<\gamma\gamma|H_{\rm eff}|N>+c_s <\gamma\gamma|H_{\rm eff}|S>\\ &+c_G<\gamma\gamma|H'_{\rm eff}|G>, \end{aligned}$
and because
$H_{\rm eff}'$ is a loop-induced effective Hamiltonian, it suffers an$ {\cal O}({\alpha_s\over\pi}) $ suppression [47] compared to$H_{\rm eff}$ . A detailed computation of the box-diagram has been given in the literature, but here we just make an order of magnitude estimate, which is enough for the present experimental accuracy.With this principle, here let us make a prediction of
$ F_i\to \gamma\gamma $ for$ f_0(1370) $ ,$ f_0(1500) $ and$ f_0(1710) $ based on the values we have obtained in this work. As a comparison we list what the authors of Ref. [17] predicted$\begin{aligned}[b] & \Gamma(f_0(1370) \to \gamma\gamma):\Gamma(f_0(1500) \to \gamma\gamma) :\Gamma(f_0(1710) \to \gamma\gamma)\\ & \qquad = 9.3:1.0:1.7 \end{aligned}$
(31) through the relation
$ \Gamma(F_i \to \gamma\gamma)\sim \left({5\over9}{c_{i1}\over\sqrt2}+ {1\over9}c_{i2}\right)^2 ,$
(32) where they neglected the contribution of the glueball component in
$ F_i $ due to the$ {\cal O}({\alpha_s\over\pi}) $ suppressed contribution to the amplitude. Although the contribution from the glueball component is suppressed, it may reach the error range determined by accurate measurement, thus in our calculation we present the ratios of$ F_i\to \gamma\gamma $ with and without considering the contribution of the glueball:$ \Gamma(F_i \to \gamma\gamma)\sim \Bigg|{1\over\sqrt3}\left({5\over9}{c_{i1}\over\sqrt2}+ {1\over9}c_{i2}\right)+ {{\rm Tr}[t^a t^a]\over\sqrt8}{\cal O}\left({\alpha_s\over\pi}\right){6\over9}c_{i3}\Bigg|^2. $
(33) In our numerical calculations we take
$ \alpha_s\sim 0.3 $ as a example. We list the corresponding results in Table 4.results from Ref. [17] without glueball component with glueball component $\dfrac{\Gamma(f_0(1370) \to \gamma\gamma)}{\Gamma(f_0(1500) \to \gamma\gamma)}$ 9.3 $ 27.2\sim1.93\times10^7 $ $ 19.0\sim3208.3 $ $\dfrac{\Gamma(f_0(1710) \to \gamma\gamma)}{\Gamma(f_0(1500) \to \gamma\gamma)}$ 1.7 $ 5.8\sim4.13\times10^6 $ $ 0.003\sim33.0 $ $\dfrac{\Gamma(f_0(1710) \to \gamma\gamma)}{\Gamma(f_0(1370) \to \gamma\gamma)}$ 0.183 $ 0.087\sim0.261 $ $ 6.8\times10^{-5}\sim0.016 $ Table 4. Ratios of
$ F_i\to \gamma\gamma $ with and without considering the contribution from the glueball component.From the table above we find that without considering the contribution from the glueball component, the upper limits of
$ \Gamma(f_0(1370) \to \gamma\gamma)/\Gamma(f_0(1500) \to \gamma\gamma) $ and$ \Gamma(f_0(1710) \to \gamma\gamma)/\Gamma(f_0(1500) \to \gamma\gamma) $ are extremely large, because of a destructive interference between the$ n\bar n $ and$ s\bar s $ contributions to$ f_0(1500)\to \gamma\gamma $ . Taking into account the contribution from the glueball component, the lower limit of$ \Gamma(f_0(1710) \to \gamma\gamma)/\Gamma(f_0(1370) \to \gamma\gamma) $ is tiny. This is caused by the destructive interference between the contributions of the glueball and quarkonia ingredients to$ f_0(1710)\to \gamma\gamma $ , whereas the upper bound of$ \Gamma(f_0(1370)\to \gamma\gamma)/ \Gamma(f_0(1500)\to\gamma\gamma) $ is very large, which is caused by the destructive interference between$ n\bar n $ and$ s\bar s $ contributions to$ f_0(1500)\to\gamma\gamma $ .Apart from these extreme cases, we find that the decay width of
$ f_0(1710) \to \gamma\gamma $ is smaller than that of$ f_0(1370) \to \gamma\gamma $ by one or two orders of magnitude for our structure assignments, i.e in$ f_0(1710) $ the glueball component is dominant while in$ f_0(1370) $ the quark component is dominant. The decay width of$ f_0(1370) \to \gamma\gamma $ is larger than that of$ f_0(1500) \to \gamma\gamma $ due to the fact that the$ n\bar n $ and$ s\bar s $ components constructively interfere for$ f_0(1370) $ whereas they destructively interfere for$ f_0(1500) $ in our scenario. The prediction is somewhat different from that made by Cheng et al. [17]. The comparison is shown in the above tables.
Revisiting the determining fraction of glueball component in f0 mesons via radiative decays of J/ψ
- Received Date: 2020-08-13
- Available Online: 2021-02-15
Abstract: QCD theory predicts the existence of glueballs, but so far all experimental endeavors have failed to identify any such states. To remedy this discrepancy between QCD, which has proven to be a successful theory for strong interactions, and the failure of experimental searches for glueballs, one is tempted to accept the promising interpretation that the glueballs mix with regular