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First, we briefly review the aether scalar tensor (AeST) theory. The action constructed by a scalar ϕ and a unit-timelike vector
$ A_{\mu} $ excluding the metric$ g_{\mu\nu} $ , is given by$ S=S_G+S_M $ , where$ S_M $ is the action of the ordinary matter field explicitly independent of ϕ and$ A_{\mu} $ , and$ S_G $ is expressed as [6]$ \begin{aligned}[b] S_G =& \int d^4x \frac{\sqrt{-g}}{2\kappa}\bigg[R-\frac{K_B}{2}F_{\mu\nu}F^{\mu\nu}+2(2-K_B)J^{\mu}\nabla_{\mu}\phi \\ &- (2-K_B)\mathcal{Y}-\mathcal{F}(\mathcal{Y},Q)-\lambda(A^{\mu}A_{\mu}+1)\bigg], \end{aligned} $
(1) where
$ \kappa\equiv 8\pi G_* $ , with$ G_* $ proportional to the measured value of the Newtonian gravitational constant [40],$ F_{\mu\nu}=\nabla_{\mu}A_{\nu}-\nabla_{\nu}A_{\mu} $ ,$ Q=A^{\mu}\nabla_{\mu}\phi $ ,$ \mathcal{Y}=(g^{\mu\nu}+A^{\mu}A^{\nu})\nabla_{\mu}\phi\nabla_{\nu}\phi $ ,$ J^{\mu}=A^{\nu}\nabla_{\nu}A^{\mu} $ ,$ \mathcal{F} $ is a free function of$ \mathcal{Y} $ and Q, λ is a Lagrange multiplier leading to the unit-timelike constraint$ A^{\mu}A_{\mu}+1=0 $ , and$ K_B $ is a dimensionless constant.The gravitational field equations can be derived by varying the action with respect to the metric [9, 10]:
$ R_{\mu\nu}-\frac{1}{2}g_{\mu\nu}R+\mathcal{H}_{\mu\nu}=T_{\mu\nu}, \; $
(2) where we have set
$ \kappa=1 $ and$ \begin{aligned}[b] \mathcal{H}_{\mu\nu} =& -K_B\Big(F_{\mu}^{\; \alpha}F_{\nu\alpha}-\frac{1}{4}F^{\alpha\beta}F_{\alpha\beta}\Big)-\lambda A_{\mu}A_{\nu} \\ &- (2-K_B)g_{\mu\nu}J^{\alpha}\nabla_{\alpha}\phi+2(2-K_B)\bigg(A^{\sigma}\nabla_{(\mu}\phi\nabla_{\sigma}A_{\nu)} \\ &- \frac{1}{2}A_{\mu}A_{\nu}\square\phi+\nabla_{\sigma}\phi A_{(\mu}F_{\nu)}^{\; \sigma}\bigg)+\frac{1}{2}g_{\mu\nu}\big((2-K_B)\mathcal{Y} \\ &+ \mathcal{F}\big)-\big((2-K_B)+\mathcal{F}_{\mathcal{Y}}\big)\nabla_{\mu}\phi\nabla_{\nu}\phi \\ &- \Big(2Q\big((2-K_B)+\mathcal{F}_{\mathcal{Y}}\big)+\mathcal{F}_Q\Big)A_{(\mu}\nabla_{\nu)}\phi. \end{aligned} $
(3) Here,
$ \mathcal{F}_{\mathcal{Y}}\equiv\dfrac{\partial\mathcal{F}}{\partial\mathcal{Y}} $ and$ \mathcal{F}_{Q}\equiv\dfrac{\partial\mathcal{F}}{\partial Q} $ . It can be easily shown that Eq. (2) satisfies the energy-momentum conservation$ \nabla_{\mu}T^{\mu\nu}=0 $ .Varying the action with respect to
$ A_{\mu} $ and ϕ, the vector and scalar field equations can be respectively derived as follows:$ \begin{aligned}[b] &K_B\nabla_{\mu}F^{\mu\nu}+2(2-K_B)\big(\nabla_{\mu}\phi\nabla^{\nu}A^{\mu}-\nabla_{\mu}(A^{\mu}\nabla^{\nu}\phi)\big) \\ &\quad-\lambda A^{\nu}-\frac{1}{2}\nabla^{\nu}\phi\Big(2Q\big((2-K_B)+\mathcal{F}_{\mathcal{Y}}\big)+\mathcal{F}_Q\Big)=0, \; \end{aligned} $
(4) $ \begin{aligned}[b] &\nabla_{\mu}(\mathcal{F}_Q A^{\mu})-2(2-K_B)\nabla_{\mu}J^{\mu}+2\nabla_{\mu}\Big(Q\big((2-K_B) \\ &\quad+\mathcal{F}_{\mathcal{Y}}\big)A^{\mu}\Big)+2\nabla_{\mu}\Big(\big((2-K_B)+\mathcal{F}_{\mathcal{Y}}\big)\nabla^{\mu}\phi\Big)=0. \; \end{aligned} $
(5) Let us now consider the flat FLRW metric, i.e.,
${\rm d}s^2=-{\rm d}t^2+a(t)^2({\rm d}r^2+r^2{\rm d}\Omega^2)$ , with$ a(t) $ denoting the cosmic scale factor. It can be easily shown that$A_{\mu}= (-1,0,0,0)$ ,$ \mathcal{Y}=0 $ ,$ J^{\mu}=0 $ , and$ Q=\dot{\phi} $ , where the dot stands for the derivative with respect to t. After defining a new functional$\mathcal{K}(Q)=-\mathcal{F}(0,Q)/2$ , Eq. (5) can be expressed as$ \nabla_{\mu}(\mathcal{K}_Q A^{\mu})=0 $ , which reduces to$\dot{\mathcal{K}}_Q+3H\mathcal{K}_Q =0$ for the FLRW metric. This equation admits the solution$\mathcal{K}_Q={I_0}/{a^3}=I_0(1+z)^3$ with$ I_0 $ being an integration constant and the usual definition of the redshift$ 1+z=1/a $ . Thus, Eq. (5) can be significantly simplified. Note that, since there is no potential term for the scalar field ϕ, it might not act as an inflaton candidate.From Eq. (4), Lagrange multiplier λ can be solved as
$ \begin{array}{*{20}{l}} \lambda=(2-K_B)(\dot{Q}+3HQ+Q^2)-Q\mathcal{K}_Q. \end{array} $
(6) Assuming a perfect fluid with barotropic density ρ and pressure p, and substituting the Lagrange multiplier into Eq. (2), one can obtain
$ H^2=\frac{\rho}{3}+\frac{1}{3} Q \mathcal{K}_{Q}-\frac{1}{3} \mathcal{K},\; $
(7) $ \frac{2}{3} \dot{H}+H^2=-\frac{p}{3}-\frac{1}{3} \mathcal{K}.\; $
(8) Then, subtracting Eq. (7) from Eq. (8) yields
$ \begin{array}{*{20}{l}} 2 \dot{H}+p+Q \mathcal{K}_{Q}+\rho=0.\; \end{array} $
(9) It is well-known that present cosmological observations suggest that the Hubble parameter in terms of the redshift is described as
$ H(z)=\sqrt{\frac{\rho_0}{3} (1+z)^3+\frac{\Lambda }{3}},\; $
(10) where
$ \rho_0 $ is the present matter density and Λ is the cosmological constant. Now, we have four unknown functions to be solved, i.e., H, ρ, p, and$ \mathcal{K}(Q) $ . In what follows, we aim to reconstruct the functional$ \mathcal{K}(Q) $ that can exactly mimic the above expansion history with different matter contents. -
First, we reconstruct the functional
$ \mathcal{K}(Q) $ that can reproduce the ΛCDM background only with dust-like matter. From the continuity equation$ \dot{\rho}+3H(\rho+p)=0 $ and equation of state (EoS)$ p=w\rho=0 $ , one obtains$ \rho=\dfrac{\rho_0}{a^3} $ . Then, inserting the density ρ and$ \mathcal{K}_Q=I_0(1+z)^3 $ into Eq. (9) and transforming it to the z coordinate, the scalar Q in terms of the redshift can be expressed as$ Q(z)=\frac{2 H H'-\rho_0 (1+z)^2}{I_0 (1+z)^2}, $
(11) where the prime denotes the derivative with respect to z. However, by inserting Eq. (10) into Eq. (11), we immediately have
$ Q=0 $ , i.e., the AeST theory reduces to GR, which indicates that this theory does not admit the ΛCDM solution only with dust-like matter. -
In this case, we reconstruct
$ \mathcal{K}(Q) $ for a perfect fluid with$p=-\rho/3$ , which is interesting because it resides on the boundary of the set of matter fields that adhere to the strong energy condition. Then, from the continuity equation, the density and pressure of the perfect fluid can be obtained as$ \rho=\rho_0(1+z)^2 $ and$p=- \rho_0 (1+z)^2/3$ , respectively. Inserting ρ and p into Eq. (9), one can obtain$ Q(z)=-\frac{2 \left(-3 H H'+\rho_0(1+z)\right)}{3 I_0 (1+z)^2}.\; $
(12) Inserting Eq. (10) into Eq. (12) and inverting it, we have
$ z=\frac{\rho_0-3 I_0 Q}{3 (I_0 Q-\rho_0)}. $
(13) Then, from Eq. (8), the functional
$ \mathcal{K}(Q) $ can be calculated as$ \mathcal{K}(Q)=\frac{1}{3} \rho_0 (1+z)^2=\frac{4 \rho_0^3}{27 (\rho_0-I_0 Q)^2}-\Lambda. $
(14) -
In general, our universe contains multiple matter components. In this case, we consider matter contents that include dust-like matter and also a noninteracting stiff fluid. Their densities are
$ \rho_0 $ and$ \rho_s $ , respectively, and the total matter density is given by$ \rho=\frac{\rho_0}{a^3}+\frac{\rho_s}{a^6}. $
(15) With the help of the continuity equation, the EoS parameter can be calculated as
$ w=\frac{\rho_s}{\rho_s+\dfrac{\rho_0}{(1+z)^3}}. $
(16) Thus, the pressure is
$ p=w\rho=\rho_s (1+z)^6 $ . Substituting ρ, p, and$ \mathcal{K}_Q $ into Eq. (9), the scalar Q can be derived as$ Q(z)=\frac{2HH'-(1+z)^2(\rho_0+2(1+z)^3\rho_s)}{I_0(1+z)^2}. $
(17) Assuming the ΛCDM background and inverting the above expression, one obtains
$ z=-\left(\frac{I_0 Q}{2\rho_s}\right)^{1/3}-1. $
(18) From Eq. (8),
$ \mathcal{K}(Q) $ can be solved as$ \mathcal{K}(Q)=-\frac{I_0^2 Q^2}{4 \rho_s}-\Lambda. $
(19) Therefore, if the universe is filled with noninteracting stiff fluid and dust-like matter, it is impossible to distinguish the AeST theory from GR using the current cosmological observations at the background level, given that this theory accurately replicates an expansion history consistent with the ΛCDM model.
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The EoS of nonisentropic perfect fluids can be expressed as
$ \begin{array}{*{20}{l}} p=h(\rho, a). \end{array} $
(20) In this case, the continuity equation becomes
$ \frac{{\rm d}\rho}{{\rm d}a}+\frac{3}{a}(\rho+h)=0. \; $
(21) Usually, Eq. (21) may not have a solution in closed form. However, if
$ h(\rho, a) $ can be expressed as a separable function in the form of$ p=h(\rho, a)=w(a)\rho $ , the calculations become considerably easier, and the solution is$ \rho(a)=c_1\text{exp}\left(-3\int\frac{1+w(a)}{a}{\rm d}a\right). $
(22) As an example, let us consider an explicit time-dependent barotropic index given by
$ w(a)=\frac{2 \gamma -a^3 \nu }{a^3 \nu +\gamma }, $
(23) where γ and ν are constants. Then, we have
$ \rho(a)=c_1 \frac{(\gamma+a^3\nu)^3}{a^9}, \; $
(24) where
$ c_1=\dfrac{\rho_0}{(\gamma+\nu)^3} $ . The substitution of Eq. (24) into Eq. (9) yields$ Q=\frac{2 H H'}{I_0 (1+z)^2}-\frac{\left(3 c_1 \gamma \right) \left(\nu +\gamma (1+z)^3\right)^2}{I_0}. $
(25) Considering the ΛCDM background, the above expression admits the following inverse solution:
$ z=-1+\left(-\frac{\nu }{\gamma }\pm\sqrt{\frac{\rho _0-I_0 Q}{3 c_1 \gamma ^3}}\right)^{1/3}. $
(26) From Eq. (8), the particular solution for
$ \mathcal{K}(Q) $ can be solved as$ \mathcal{K}(Q)=\frac{\left(-\rho _0+I_0 Q\right) \left(-9 \nu \pm2 \sqrt{3} \sqrt{\dfrac{\rho _0-I_0 Q}{c_1 \gamma}}\right)}{9 \gamma }-\Lambda. $
(27) As another form of nonisentropic perfect fluids, we consider that the EoS is given by
$ p=w\rho + h(a) $ . Thus, the solution of Eq. (21) can be expressed as$ \rho(a)=a^{-3 (w+1)} \left(c_2-\int 3 h(a) a^{(3 w+2)} {\rm d}a\right), $
(28) As a further specific example, let us consider
$ h(a)=\dfrac{h_0}{a^{12}} $ and$ w=0 $ . This suggests that the matter contents within the universe can be approximated as dust, accompanied by a time-dependent cosmological term that diverges at the singularity of the big bang and diminishes rapidly during subsequent epochs. Then, the density$ \rho(a) $ is expressed as$ \rho(a)=\frac{c_2}{a^3}+\frac{h_0}{3a^{12}}, $
(29) where
$ c_2=\rho_0-\dfrac{h_0}{3} $ . From Eq. (9), the scalar Q can be obtained as$ Q=-\frac{c_2}{I_0}+\frac{2 H H'}{I_0 (1+z)^2}-\frac{4h_0(1+z)^9}{3 I_0}. $
(30) Assuming the ΛCDM background and inverting the above expression, one obtains
$ z=-1+\left[\frac{1}{4} \left(1-\frac{3 I_0 Q}{h_0}\right)\right]^{1/9}, $
(31) where we have inserted
$ c_2=\rho_0-\dfrac{h_0}{3} $ . Solving Eq. (8), we obtain the following solution:$ \mathcal{K}(Q)=-h_0\left[\frac{1}{4} \left(1-\frac{3 I_0 Q}{h_0}\right)\right]^{4/3}-\Lambda. $
(32) The above explicit reconstructions for replicating the ΛCDM-era were also explored in other physical models, such as the k-essence model, and
$ f(R) $ and$ f(Q) $ gravity. Please, consult Refs. [37, 41−43] for further details. -
In this section, we are interested in finding the explicit solutions of
$ \mathcal{K}(Q) $ that can replicate the ΛCDM-era with no real matter, i.e.,$ \rho=p=0 $ . In this case, the scalar Q solved from Eq. (9) reduces to$ Q=\frac{2H H'}{I_0(1+z)^2}. $
(33) In the following, we solve this system using some cosmological models. As a first example, we consider the Chaplygin gas model, in which the universe evolves from a dust-matter dominated phase at early times to a cosmological constant dominated phase at late times. The FLRW equation for this model is given by [44]
$ H^2=\sqrt{A+B(1+z)^6}, $
(34) where A is a positive constant and B is an integration constant. Then, by inverting Eq. (33), one can obtain
$ z=-1\pm\frac{\sqrt[6]{I_0^2 A B^2 Q^2 \left(-9 B+I_0^2 Q^2\right){}^2}}{\sqrt{B \left(9 B-I_0^2 Q^2\right)}}. $
(35) From Eq. (8), the funtional
$ \mathcal{K}(Q) $ can be solved as$ \mathcal{K}(Q)=-\sqrt{\frac{A}{B} \left(9 B-I_0^2 Q^2\right)}. $
(36) Thus, we have demonstrated that the AeST theory admits the Chaplygin gas cosmological solution without introducing any real matter.
As another example, let us consider the following phantom-non-phantom model [45]
$ H^2=\frac{1}{3} \rho_p (1+z)^b+\frac{\rho_q}{3 (1+z)^d}, \; $
(37) where
$ \rho_p $ ,$ \rho_q $ , b, and d are positive constants. The first term in the right hand side of the above equation dominates in the early universe, which behaves as non-phantom matter with EoS parameter$w_p=-1 + b/3 > -1$ in the Einstein gravity, while the second term dominates in the late universe and behaves as a phantom matter with$ w_d=-1-d/3<-1 $ . To mimic the late-time behavior of the universe, we set$ b=3 $ . Then, by inverting Eq. (33), we obtain$ z=-1+\left(\frac{3 \left(\rho _p-I_0 Q\right)}{d \rho _q}\right){}^{-\frac{1}{d+3}}. $
(38) From Eq. (8),
$ \mathcal{K}(Q) $ can be solved as$ \mathcal{K}(Q)= -\frac{1}{3} (d+3) \rho_q \left(\frac{3 \rho_p-3 I_0 Q}{d \rho_q}\right)^{\frac{d}{d+3}}. $
(39) Thus, the AeST theory is capable of reproducing the solution of Eq. (37), where the parameters
$ b=3 $ and$ d\geqslant 0 $ represent the ΛCDM model. Moreover, it is plausible that this solution propels the evolution of the universe towards a phantom phase in the foreseeable future. -
In this section, we focus on exploring the feasibility of obtaining a well-suited functional
$ \mathcal{K}(Q) $ for simulating the cosmic evolution resulting from both the power-law and de-Sitter solutions. -
It is interesting to explore the presence of precise power-law solutions within the framework of AeST gravitational theory for different cosmic evolution stages. These solutions correspond to the decelerated and accelerated cosmic eras, which are characterized by the scale factor
$ a(t)=a_0 t^m, \quad H(t)=\frac{m}{t}, $
(40) where
$ m>0 $ . The universe undergoes a decelerated phase for$ 0 < m < 1 $ and experiences an accelerated phase for$ m>1 $ . To solve the system completely, we need another initial condition. Here, we reconstruct the funtional$ \mathcal{K}(Q) $ with some given matter contents as the initial conditions.First, for dust-like matter with
$ p=0 $ and$ \rho=\rho_0/a^3 $ , Eq. (9) leads to$ Q=\frac{2 a_0^3 m}{I_0}t^{3 m-2}-\frac{\rho_0}{I_0}. $
(41) Inverting the above expression, we obtain
$ t=\left(\frac{\rho _0+I_0 Q}{2 a_0^3 m}\right)^{\frac{1}{3m-2}}. $
(42) After a straightforward calculation,
$ \mathcal{K}(Q) $ can be obtained as$ \mathcal{K}(Q)=(2-3 m) m \left(\frac{\rho _0+I_0 Q}{2 a_0^3 m}\right)^{\frac{2}{2-3 m}}. $
(43) Second, for a perfect fluid with pressure
$p=-\dfrac{1}{3}\rho$ , the scalar Q can be solved as$ Q=\frac{6 a_0^3 m t^{3 m-2}-2 a_0 \rho _0 t^m}{3 I_0}.\; $
(44) However, the above expression does not admit an analytical inverse solution for a general m. Thus, without loss of generality, we take two particular values of m as examples, i.e.,
$m=\dfrac{1}{2}$ and$ m=2 $ , which correspond to a decelerated phase and an accelerated phase, respectively. For$m=\dfrac{1}{2}$ , the inverse solution of Eq. (44) is calculated as$ t=\frac{9 I_0^2 Q^2+12 a_0^4 \rho _0\pm 3 \sqrt{24 I_0^2 a_0^4 \rho _0 Q^2+9 I_0^4 Q^4}}{8 a_0^2 \rho _0^2}, $
(45) and then the solution of
$ \mathcal{K}(Q) $ derived from Eq. (8) is$ \mathcal{K}=\frac{8 \rho _0^3 \left(3 I_0^2 Q^2 + 6 a_0^4 \rho _0 \pm \sqrt{24 I_0^2 a_0^4 \rho _0 Q^2 + 9 I_0^4 Q^4}\right)}{9 \left(\pm3I_0^2 Q^2 \pm 4 a_0^4 \rho _0 + \sqrt{24 I_0^2 a_0^4 \rho _0 Q^2 + 9 I_0^4 Q^4}\right)^2}.\; $
(46) For
$ m=2 $ , the inverse solution of Eq. (44) is derived as$ t=\frac{\sqrt{\rho _0\pm \sqrt{\rho _0^2+36 I_0 a_0 Q}}}{2 \sqrt{3} a_0}, $
(47) and the functional
$ \mathcal{K}(Q) $ is$ \mathcal{K}(Q)=-\frac{48 a_0^3 \left(\rho _0\pm 2 \sqrt{\rho _0^2+36 I_0 a_0 Q}\right)}{\left(\pm \rho _0+\sqrt{\rho _0^2+36 I_0 a_0 Q}\right)^2}. $
(48) Finally, for a perfect fluid with EoS
$ p=-\rho $ , the scalar Q is solved as$ Q=\frac{2 a_0^3 m}{I_0}t^{3 m-2}, $
(49) with
$t=\left(\dfrac{I_0 Q}{2 a_0^3 m}\right)^{\frac{1}{3m-2}}$ being its inverse solution. Then, the functional$ \mathcal{K}(Q) $ can be calculated as$ \mathcal{K}(Q)=\rho _0+m (2-3 m) \left(\frac{I_0 Q}{2 a_0^3 m}\right){}^{\frac{2}{2-3 m}}. $
(50) Thus, we have explicitly demonstrated that it is possible to reconstruct the pow-law solution within the AeST theory.
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The de-Sitter cosmic evolution is a widely recognized model because it effectively represents the expansion of the universe. According to this model, the universe experiences constant expansion during the epoch dominated by dark energy, and the scale factor exhibits exponential growth with a constant Hubble parameter
$ H(t)=H_0 $ , expressed as$ a(t)=a_0\text{e}^{H_0 t}. $
(51) For the above scale factor and general EoS
$ p=w\rho $ , the scalar Q can be explicitly solved as$ Q=-\frac{\rho _0 (w+1) \left(a_0 {\rm e}^{H_0 t}\right)^{-3 w}}{I_0}, $
(52) which admits the following analytical inverse solution
$ t=\frac{1}{H_0 w}\ln \left[\frac{1}{a_0w}\left(\frac{\rho_0(1+w)}{I_0 Q}\right)^{1/3}\right]. $
(53) Solving Eq. (8) directly, we obtain
$ \mathcal{K}(Q)=-3 H_0^2-w \rho_0\left(-\frac{\rho_0(1+w)}{I_0 Q}\right)^{-(1+w)/w}. $
(54) It is clear that the de-Sitter solution can be achieved within the framework of the AeST theory.
Reconstruction of aether scalar tensor theory for variouscosmological scenarios
- Received Date: 2023-11-01
- Available Online: 2024-04-15
Abstract: In this paper, we present several explicit reconstructions for the aether scalar tensor (AeST) theory derived from the background of the Friedmann-Lemaître-Robertson-Walker cosmological evolution. It is shown that the Einstein-Hilbert Lagrangian with a positive cosmological constant is the only Lagrangian capable of accurately replicating the exact expansion history of the Λ cold dark matter (ΛCDM) universe filled solely with dust-like matter. However, the ΛCDM-era can be produced within the framework of the AeST theory for some other fluids, including a perfect fluid with